A charged particle of mass 5 times {10^{ - 5} | vedclass

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Question

(b) $QE = mg$ $ \Rightarrow \,Q = \frac{{mg}}{E} = \frac{{5 	imes {{10}^{ - 5}} 	imes 10}}{{{{10}^7}}}= 5 	imes 10^{-5}\,\mu C.$
Since electric fi

Vedclass · Accepted Answer

$ - 5 	imes {10^{ - 5}}\,\mu C$

Vedclass · Answer

(b) $QE = mg$ $ \Rightarrow \,Q = \frac{{mg}}{E} = \frac{{5 	imes {{10}^{ - 5}} 	imes 10}}{{{{10}^7}}}= 5 	imes 10^{-5}\,\mu C.$
Since electric field is acting downward so for balance charge must be negative.

A charged particle of mass $5 \times {10^{ - 5}}\,kg$ is held stationary in space by placing it in an electric field of strength ${10^7}\,N{C^{ - 1}}$ directed vertically downwards. The charge on the particle is

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