Gujarati
Hindi
10-1.Circle and System of Circles
normal

A circle is drawn with $y- $ axis as a tangent and its centre at the point which is the reflection of $(3, 4)$ in the line $y = x$. The equation of the circle is

A

$x^2 + y^2 - 6x - 8y + 16 = 0$

B

$x^2 + y^2 - 8x - 6y + 16 = 0$

C

$x^2 + y^2 - 8x - 6y + 9 = 0$

D

$x^2 + y^2 - 6x - 8y + 9 = 0$

Solution

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Standard 11
Mathematics

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