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10-1.Circle and System of Circles
easy
A circle with centre $(a, b)$ passes through the origin. The equation of the tangent to the circle at the origin is
A
$ax - by = 0$
B
$ax + by = 0$
C
$bx - ay = 0$
D
$bx + ay = 0$
Solution

(b) Obviously the slope of the tangent will be $ – \left( {\frac{1}{{b/a}}} \right)$
$i.e.$, $ – \frac{a}{b}$.
Hence the equation of the tangent is
$y = – \frac{a}{b}x\;$
$i.e.$, $by + ax = 0$.
Standard 11
Mathematics