Gujarati
10-1.Circle and System of Circles
easy

A circle with centre $(a, b)$ passes through the origin. The equation of the tangent to the circle at the origin is

A

$ax - by = 0$

B

$ax + by = 0$

C

$bx - ay = 0$

D

$bx + ay = 0$

Solution

(b) Obviously the slope of the tangent will be $ – \left( {\frac{1}{{b/a}}} \right)$

$i.e.$, $ – \frac{a}{b}$.

Hence the equation of the tangent is

$y = – \frac{a}{b}x\;$

$i.e.$, $by + ax = 0$.

Standard 11
Mathematics

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