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1. Electric Charges and Fields
easy
A cube of side $b$ has a charge $q$ at each of its vertices. The electric field due to this charge distribution at the centre of this cube will be
A
$q/{b^2}$
B
$q/2{b^2}$
C
$32q/{b^2}$
D
Zero
Solution
(d) Due to symmetric charge distribution.
Standard 12
Physics