A cubical block of side 0.5,m floats on water with 30% of its volume under water. ....... kg is maxi

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9-1.Fluid Mechanics

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A cubical block of side $0.5\,m$ floats on water with $30\%$ of its volume under water. ....... $kg$ is the maximum weight that can be put on the block without fully submerging it under water ? [Take density of water $= 10^3\,kg/m^3$ ]

A

$46.3$

B

$65.4$

C

$30.1$

D

$87.5$

(JEE MAIN-2019)

Solution

$0.3\,{\ell ^3}\,{\rho _\omega } = {\ell ^3}\rho $

$\rho = 300\frac{{kg}}{{{m^3}}}$

$m + {\ell ^3}\rho = {\ell ^3}{\rho _\omega }$

$M = {\ell ^3}\left( {{\rho _w} – \rho } \right) = {\left( 0.5 \right)^3}\left\{ {1000 – 300} \right\}$

$ = 700 \times {\left( 0.5 \right)^3}$

$ = 87.5\,kg$

Standard 11

Physics

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