A die marked $1,\,2,\,3$ in red and $4,\,5,\,6$ in green is tossed. Let $A$ be the event, $'$ the number is even,$'$ and $B$ be the event, 'the number is red'. Are $A$ and $B$ independent?
When a die is thrown, the sample space ( $S$ ) is
$\mathrm{S}=\{1,2,3,4,5,6\}$
Let $A:$ the number is even $=\{2,4,6\}$
$\Rightarrow P(A)=\frac{3}{6}=\frac{1}{2}$
$B:$ the number is red $=\{1,2,3\}$
$\Rightarrow P(B)=\frac{3}{6}=\frac{1}{2}$
$\therefore $ $A \cap B=\{2\}$
$P(A B)=P(A \cap B)=\frac{1}{6}$
$P(A) P(B)=\frac{1}{2} \times \frac{1}{2}=\frac{1}{4} \neq \frac{1}{6}$
$\Rightarrow $ $P(A) \cdot P(B) \neq P(A B)$
Therefore, $A$ bad $B$ are not independent.
Two persons $A$ and $B$ throw a (fair)die (six-faced cube with faces numbered from $1$ to $6$ ) alternately, starting with $A$. The first person to get an outcome different from the previous one by the opponent wins. The probability that $B$ wins is
Given two independent events $A$ and $B$ such that $P(A) $ $=0.3, \,P(B)=0.6$ Find $P(A$ and $B)$.
Three coins are tossed simultaneously. Consider the event $E$ ' three heads or three tails', $\mathrm{F}$ 'at least two heads' and $\mathrm{G}$ ' at most two heads '. Of the pairs $(E,F)$, $(E,G)$ and $(F,G)$, which are independent? which are dependent ?
The probability of happening at least one of the events $A$ and $B$ is $0.6$. If the events $A$ and $B$ happens simultaneously with the probability $0.2$, then $P\,(\bar A) + P\,(\bar B) = $
$A$ and $B$ are two events such that $P(A)=0.54$, $P(B)=0.69$ and $P(A \cap B)=0.35.$ Find $P \left( B \cap A ^{\prime}\right)$.