A die marked $1,\,2,\,3$ in red and $4,\,5,\,6$ in green is tossed. Let $A$ be the event, $'$ the number is even,$'$ and $B$ be the event, 'the number is red'. Are $A$ and $B$ independent?
When a die is thrown, the sample space ( $S$ ) is
$\mathrm{S}=\{1,2,3,4,5,6\}$
Let $A:$ the number is even $=\{2,4,6\}$
$\Rightarrow P(A)=\frac{3}{6}=\frac{1}{2}$
$B:$ the number is red $=\{1,2,3\}$
$\Rightarrow P(B)=\frac{3}{6}=\frac{1}{2}$
$\therefore $ $A \cap B=\{2\}$
$P(A B)=P(A \cap B)=\frac{1}{6}$
$P(A) P(B)=\frac{1}{2} \times \frac{1}{2}=\frac{1}{4} \neq \frac{1}{6}$
$\Rightarrow $ $P(A) \cdot P(B) \neq P(A B)$
Therefore, $A$ bad $B$ are not independent.
In two events $P(A \cup B) = 5/6$, $P({A^c}) = 5/6$, $P(B) = 2/3,$ then $A$ and $B$ are
If $P(B) = \frac{3}{4}$, $P(A \cap B \cap \bar C) = \frac{1}{3}{\rm{ }}$ and $P(\bar A \cap B \cap \bar C) = \frac{1}{3},$ then $P(B \cap C)$ is
In a class of $60$ students, $30$ opted for $NCC$ , $32$ opted for $NSS$ and $24$ opted for both $NCC$ and $NSS$. If one of these students is selected at random, find the probability that The student opted for $NCC$ or $NSS$.
The probability that at least one of the events $A$ and $B$ occurs is $3/5$. If $A$ and $B$ occur simultaneously with probability $1/5$, then $P(A') + P(B')$ is
The chances to fail in Physics are $20\%$ and the chances to fail in Mathematics are $10\%$. What are the chances to fail in at least one subject ............ $\%$