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14.Probability
easy
Given $P(A)=\frac{3}{5}$ and $P(B)=\frac{1}{5}$. Find $P(A $ or $B),$ if $A$ and $B$ are mutually exclusive events.
A
$\frac{4}{5}$
B
$\frac{4}{5}$
C
$\frac{4}{5}$
D
$\frac{4}{5}$
Solution
Here, $P ( A )=\frac{3}{5} $, $P ( B )=\frac{1}{5}$
For mutually exclusive events $A$ and $B,$
$P ( A $ or $B )= P ( A )+ P ( B )$
$P ( A $ or $B )=\frac{3}{5}+\frac{1}{5}=\frac{4}{5}$
Standard 11
Mathematics