Given P(A)=frac{3}{5} and P(B)=frac{1}{5} . Find P(A or B), if A and B are mutually exc

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14.Probability

easy

Given $P(A)=\frac{3}{5}$ and $P(B)=\frac{1}{5}$. Find $P(A $ or $B),$ if $A$ and $B$ are mutually exclusive events.

A

$\frac{4}{5}$

B

$\frac{4}{5}$

C

$\frac{4}{5}$

D

$\frac{4}{5}$

Solution

Here, $P ( A )=\frac{3}{5} $, $P ( B )=\frac{1}{5}$

For mutually exclusive events $A$ and $B,$

$P ( A $ or $B )= P ( A )+ P ( B )$

$P ( A $ or $B )=\frac{3}{5}+\frac{1}{5}=\frac{4}{5}$

Standard 11

Mathematics

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