A gas ( gamma = 1.3) is enclosed in an insulated vessel fitted with insulating piston at a pressure

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11.Thermodynamics

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A gas ($\gamma = 1.3)$ is enclosed in an insulated vessel fitted with insulating piston at a pressure of ${10^5}\,N/{m^2}$. On suddenly pressing the piston the volume is reduced to half the initial volume. The final pressure of the gas is

${2^{0.7}} \times {10^5}$

${2^{1.3}} \times {10^5}$

${2^{1.4}} \times {10^5}$

None of these

Solution

(b)$\because \;P{V^\gamma } = k$(constant) ==> ${P_1}V_1^\gamma = {P_2}V_2^\gamma $
$⇒$ ${P_2} = {P_1}{\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^\gamma } = {10^5} \times {(2)^{1.3}}$ $(\because \;{V_2} = \frac{{{V_1}}}{2})$

Standard 11

Physics

A polyatomic gas $\left( {\gamma = \frac{4}{3}} \right)$ is compressed to $\frac{1}{8}$ of its volume adiabatically. If its initial pressure is ${P_o}$, its new pressure will be

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The given diagram shows four processes i.e., isochoric, isobaric, isothermal and adiabatic. The correct assignment of the processes, in the same order is given by

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(JEE MAIN-2019)

The pressure $P_{1}$ and density $d_{1}$ of diatomic gas $\left(\gamma=\frac{7}{5}\right)$ changes suddenly to $P _{2}\left(> P _{1}\right)$ and $d _{2}$ respectively during an adiabatic process. The temperature of the gas increases and becomes $……$ times of its initial temperature.$\left(\right.$ given $\left.\frac{ d _{2}}{ d _{1}}=32\right)$

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(JEE MAIN-2022)

The pressure in the tyre of a car is four times the atmospheric pressure at $300 K$. If this tyre suddenly bursts, its new temperature will be $(\gamma = 1.4)$

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The work of $146\,kJ$ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by $7\,^oC$ . The gas is $(R = 8.3\, J\, mol^{-1}\, K^{-1})$

medium

A gas ($\gamma = 1.3)$ is enclosed in an insulated vessel fitted with insulating piston at a pressure of ${10^5}\,N/{m^2}$. On suddenly pressing the piston the volume is reduced to half the initial volume. The final pressure of the gas is

Solution

Similar Questions

A polyatomic gas $\left( {\gamma = \frac{4}{3}} \right)$ is compressed to $\frac{1}{8}$ of its volume adiabatically. If its initial pressure is ${P_o}$, its new pressure will be

The given diagram shows four processes i.e., isochoric, isobaric, isothermal and adiabatic. The correct assignment of the processes, in the same order is given by

The pressure in the tyre of a car is four times the atmospheric pressure at $300 K$. If this tyre suddenly bursts, its new temperature will be $(\gamma = 1.4)$

The work of $146\,kJ$ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by $7\,^oC$ . The gas is $(R = 8.3\, J\, mol^{-1}\, K^{-1})$

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