A geostationary satellite is orbiting the earth at a height of $6\,R$ above the surface of earth ($R$ is the radius of earth). The time period of another satellite at a height of $2.5\,R$ from the surface of the earth is :-
$3 \sqrt 2 \,hour$
$6 \sqrt 2\, hour$
$6\, hour$
$72\, hour$
The height at which the weight of a body becomes $1/16^{th}$, its weight on the surface of earth (radius $R$), is
At what height above the earth's surface is the value of $'g'$ is same as in a $200\, km$ deep mine ........ $km$
The orbital velocity of an artificial satellite in a circular orbit very close to earth is $v$. The velocity of a geo-stationary satellite orbiting in circular orbit at an altitude of $3R$ from earth's surface will be
If potential energy of a body of mass $m$ on the surface of earth is taken as zero then its potential energy at height $h$ above the surface of earth is [ $R$ is radius of earth and $M$ is mass of earth]
At what altitude will the acceleration due to gravity be $25\% $ of that at the earth’s surface (given radius of earth is $R$) ?