A large open tank has two holes in its wall. | vedclass

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Question

(c)

Since quantities of water flowing out of both holes is same

$\Rightarrow$ Area of hole $	imes$ velocity of efflux $=$ constant

So, $A_1

Vedclass · Accepted Answer

$\frac{a}{\sqrt{2 \pi}}$

Vedclass · Answer

(c)

Since quantities of water flowing out of both holes is same

$\Rightarrow$ Area of hole $	imes$ velocity of efflux $=$ constant

So, $A_1 	imes V_1=A_2 	imes V_2$

Substituting values.

$a^2 	imes \sqrt{2 g x}=\pi r^2 	imes \sqrt{8 g x}$    $\left\{\begin{array}{l}A_1=	ext { Area of square hole } \ V_1=	ext { Velocity of efflux from square hole }=\sqrt{2 g x} \ A_2=	ext { Area of circular hole } \ V_2=	ext { Velocity of efflux from } \ \quad 	ext { circular hole }=\sqrt{2 g(4 x)}\end{array}ight.$

$\Rightarrow a^2=2 \pi r^2$

$\Rightarrow \frac{a}{\sqrt{2 \pi}}=r$

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