A light string passing over a smooth light pulley connects two block of masses m₁ and m₂ (vertic

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4-1.Newton's Laws of Motion

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A light string passing over a smooth light pulley connects two block of masses $m_1$ and $m_2$ (vertically). If the acceleration of the system is $(\frac {g}{8})$, then the ratio of masses is

A

$8 : 1$

B

$9 : 7$

C

$4 : 3$

D

$5 : 3$

Solution

$a=\left(\frac{m_{2}-m_{1}}{m_{1}+m_{2}}\right) g$

$\frac{g}{8}=\left(\frac{m_{2}-m_{1}}{m_{1}+m_{2}}\right) g$

$m_{1}+m_{2}=8 m_{2}-8 m_{1}$

$9 \mathrm{m}_{1}=7 \mathrm{m}_{2}$

$\frac{m_{2}}{m_{1}}=\frac{9}{7}$

Standard 11

Physics

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