Gujarati
Hindi
9-1.Fluid Mechanics
normal

A liquid $X$ of density $3.36\, g/cm^3$ is poured in a $U$ -tube upto $10\, cm$ height,  which  contains $Hg.$ Another liquid $Y$ is poured in left arm with height $8\, cm$. Upper  levels of $X$ and $Y$ are same. ............ $gm/cc$ is density of $Y$ .
(Density of $Hg = 13.6 \times 10^3\, kg/m^3$)

A

$0.8$

B

$1.2$

C

$1.4 $

D

$1.6$

Solution

$\mathrm{P}_{\mathrm{A}}=\mathrm{P}_{\mathrm{B}}$

$10 \times \rho_{x} \times g=8 \rho_{y} g+2 \rho_{H g} g$

$10 \times 3.36=8 \rho_{y}+2 \times 13.6$

$\rho_{y}=0.8 \mathrm{g} / \mathrm{cm}^{3}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.