- Home
- Standard 11
- Physics
9-1.Fluid Mechanics
normal
A liquid $X$ of density $3.36\, g/cm^3$ is poured in a $U$ -tube upto $10\, cm$ height, which contains $Hg.$ Another liquid $Y$ is poured in left arm with height $8\, cm$. Upper levels of $X$ and $Y$ are same. ............ $gm/cc$ is density of $Y$ .
(Density of $Hg = 13.6 \times 10^3\, kg/m^3$)

A
$0.8$
B
$1.2$
C
$1.4 $
D
$1.6$
Solution

$\mathrm{P}_{\mathrm{A}}=\mathrm{P}_{\mathrm{B}}$
$10 \times \rho_{x} \times g=8 \rho_{y} g+2 \rho_{H g} g$
$10 \times 3.36=8 \rho_{y}+2 \times 13.6$
$\rho_{y}=0.8 \mathrm{g} / \mathrm{cm}^{3}$
Standard 11
Physics