A mass m is suspended from a spring of length l and force constant $K$. The frequency of vibration of the mass is ${f_1}$. The spring is cut into two equal parts and the same mass is suspended from one of the parts. The new frequency of vibration of mass is ${f_2}$. Which of the following relations between the frequencies is correct
${f_1} = \sqrt 2 {f_2}$
${f_1} = {f_2}$
${f_1} =2 {f_2}$
${f_2} = \sqrt 2 {f_1}$
The vertical extension in a light spring by a weight of $1\, kg$ suspended from the wire is $9.8\, cm$. The period of oscillation
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