4-1.Newton's Laws of Motion
medium

Calculate $T_1$ and $T_2$

A

$\frac{{\sqrt 3 }}{2}mg,\frac{{mg}}{2}$

B

$mg,\frac{{\sqrt 3 }}{2}mg$

C

$\frac{{\sqrt 3 }}{2}mg,\frac{{\sqrt 3 }}{2}mg$

D

$\frac{{mg}}{2},\frac{{mg}}{2}$

Solution

$\frac{\mathrm{T}_{1}}{\sin 120^{\circ}}=\frac{\mathrm{Mg}}{\sin 90^{\circ}}$

$\mathrm{T}_{1}=\frac{\sqrt{3}}{2} \mathrm{Mg}$

$\frac{\mathrm{T}_{2}}{\sin 150^{\circ}}=\frac{\mathrm{Mg}}{\sin 90^{\circ}}$

$\mathrm{T}_{2}=\frac{\mathrm{Mg}}{2}$

Standard 11
Physics

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