A mass of 100,g strikes the wall with speed 5 | vedclass

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Question

(c)Force = Rate of change of momentum
Initial momentum ${\vec P_1} = mv\sin 	heta \;\hat i + mv\cos 	heta \,\hat j$
Final momentum ${\vec P_2} = -

Vedclass · Accepted Answer

$250\sqrt 3 $N to left

Vedclass · Answer

(c)Force = Rate of change of momentum
Initial momentum ${\vec P_1} = mv\sin 	heta \;\hat i + mv\cos 	heta \,\hat j$
Final momentum ${\vec P_2} = - mv\sin 	heta \;\hat i + mv\cos 	heta \,\hat j$
 $\vec F = \frac{{\Delta \vec P}}{{\Delta t}} = \frac{{ - 2mv\sin 	heta }}{{2 	imes {{10}^{ - 3}}}}$
Substituting $m = 0.1 kg, v = 5 m/s$ , $	heta = 60&deg;$
Force on the ball $\vec F = - 250\sqrt 3\, N$
Negative sign indicates direction of the force

A mass of $100\,g$ strikes the wall with speed $5\,m/s$ at an angle as shown in figure and it rebounds with the same speed. If the contact time is $2 \times {10^{ - 3}}\,\sec $, what is the force applied on the mass by the wall

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