A metal ball of density 7800 kg/m^3 is | vedclass

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Question

$9.8=7800\left(\mathrm{v}_{\mathrm{s}}\right){\mathrm{g}}$

$1.5=1000\left(\mathrm{v}_{\mathrm{s}}+\mathrm{v}_{\mathrm{e}}\right) \mathrm{g}$

$\f

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Vedclass · Answer

$9.8=7800\left(\mathrm{v}_{\mathrm{s}}ight){\mathrm{g}}$

$1.5=1000\left(\mathrm{v}_{\mathrm{s}}+\mathrm{v}_{\mathrm{e}}ight) \mathrm{g}$

$\frac{v_{s}}{v_{s}+v_{c}}=\frac{9.8}{1.5} 	imes \frac{10}{78}=83.76 \%$

$\frac{\mathrm{v}_{\mathrm{e}}}{\mathrm{v}_{\mathrm{s}}+\mathrm{v}_{\mathrm{c}}} \simeq 16 \%$

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