Gujarati
6-2.Equilibrium-II (Ionic Equilibrium)
medium

$0.1\,\,M$ विलयन में मोनोप्रोटिक अम्ल $0.001\%$ आयनित होता है । इसका आयनन नियतांक है

A

$1.0 \times {10^{ - 3}}$

B

$1.0 \times {10^{ - 6}}$

C

$1.0 \times {10^{ - 8}}$

D

$1.0 \times {10^{ - 11}}$

Solution

(d) $\therefore$ एक प्रोटिक अम्ल $HA$

$HA$ $ \rightleftharpoons $ ${H^ + } + {A^ – }$

आयनन स्थिरांक = ?

$\alpha = 0.001\,\% = \frac{{0.001}}{{100}} = {10^{ – 5}}$

$K = \frac{{{\alpha ^2}}}{V} = \frac{{{{[{{10}^{ – 5}}]}^2}}}{{10}} = {10^{ – 11}}$.

Standard 11
Chemistry

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