- Home
- Standard 12
- Physics
13.Nuclei
hard
A nucleus has mass number $A_1$ and volume $V_1$.
Another nucleus has mass number $A_2$ and volume $V_2$. If relation between mass number is $A_2=4 A_1$, then $\frac{V_2}{V_1}=$_____.
A
$3$
B
$4$
C
$5$
D
$6$
(JEE MAIN-2024)
Solution
For a nucleus
Volume: $\mathrm{V}=\frac{4}{3} \pi \mathrm{R}^3$
$\mathrm{R}=\mathrm{R}_0(\mathrm{~A})^{1 / 3}$
$\mathrm{~V}=\frac{4}{3} \pi \mathrm{R}_0^3 \mathrm{~A}$
$\Rightarrow \frac{V_2}{V_1}=\frac{A_2}{A_1}=4$
Standard 12
Physics
Similar Questions
medium