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14.Probability
easy
A number is chosen at random from first ten natural numbers. The probability that number is odd and perfect square is
A
$\frac{2}{9}$
B
$\frac{2}{5}$
C
$\frac{3}{7}$
D
$\frac{1}{5}$
Solution
(d) Odd and prefect square $( < 10)$ are $1,\,\,9.$
Hence required probability $ = \frac{2}{{10}} = \frac{1}{5}.$
Standard 11
Mathematics