Gujarati
14.Probability
easy

A number is chosen at random from first ten natural numbers. The probability that number is odd and perfect square is

A

$\frac{2}{9}$

B

$\frac{2}{5}$

C

$\frac{3}{7}$

D

$\frac{1}{5}$

Solution

(d) Odd and prefect square $( < 10)$ are $1,\,\,9.$

Hence required probability $ = \frac{2}{{10}} = \frac{1}{5}.$

Standard 11
Mathematics

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