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1.Units, Dimensions and Measurement
easy
A packet contains silver powder of mass $20.23 \,g \pm 0.01 \,g$. Some of the powder of mass $5.75 \,g \pm 0.01 \,g$ is taken out from it. The mass of the powder left back is ................
A
$14.48 \,g \pm 0.00 \,g$
B
$14.48 \pm 0.02 \,g$
C
$14.5 \,g \pm 0.1 \,g$
D
$14.5 \,g \pm 0.2 \,g$
Solution
(b)
$m_1=20.23 g \pm 0.01 \,g$
$m_2=(5.75 \pm 0.01) \,g$
$m_1-m_2=[(20.23-5.75) \pm 0.02] \,g$
$\Delta m=(14.48 \pm 0.02) \,g$
Standard 11
Physics
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