A parallel plate capacitor filled with a medium of dielectric constant 10 , is connected across a ba

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2. Electric Potential and Capacitance

hard

A parallel plate capacitor filled with a medium of dielectric constant $10$ , is connected across a battery and is charged. The dielectric slab is replaced by another slab of dielectric constant $15$ . Then the energy of capacitor will ......................

increase by $50 \%$

decrease by $15 \%$

increase by $25 \%$

increase by $33 \%$

(JEE MAIN-2022)

Solution

$E \Rightarrow \frac{1}{2}( KC ) v ^{2}$
$\therefore \%$ change
$\Rightarrow \frac{\frac{1}{2} K _{2} CV ^{2}-\frac{1}{2} K _{1} CV ^{2}}{\frac{1}{2} K _{1} CV ^{2}}=\frac{ K _{2}- K _{1}}{ K _{1}} \times 100$
$\Rightarrow \frac{15-10}{10} \times 100=50 \%$

Standard 12

Physics

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hard

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easy

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normal

(IIT-2008)

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medium