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2. Electric Potential and Capacitance
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A parallel plate capacitor has a plate separation of $0.01\, mm$ and use a dielectric (whose dielectric strength is $19\, KV/mm$) as an insulator. The maximum potential difference that can be applied to the terminals of the capacitor is......$V$
A
$190$
B
$290$
C
$95$
D
$350$
Solution
(a) Maximum potential difference
$ = 19\,\frac{{kV}}{{mm}} \times 0.01\,mm = 0.19\,kV = 190\,V$
Standard 12
Physics
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