In a capacitor of capacitance $20\,\mu \,F$, the distance between the plates is $2\,mm$. If a dielectric slab of width $1\,mm$ and dielectric constant $2$ is inserted between the plates, then the new capacitance is......$\mu \,F$

  • A

    $2$

  • B

    $15.5$

  • C

    $26.6$

  • D

    $32$

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