Angle of projection at which horizontal range and maximum height of projectile are equal is

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3-2.Motion in Plane

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The angle of projection at which the horizontal range and maximum height of projectile are equal is

A${45^o}$

B$\theta = {\tan ^{ - 1}}(0.25)$

C$\theta = {\tan ^{ - 1}}(4)$ or $\theta = 76^\circ $

D${60^o}$

Solution

(c) $R = 4H\cot \theta .$
When $R = H$ then $\cot \theta = 1/4$
$ \Rightarrow \theta = {\tan ^{ – 1}}(4)$

Standard 11

Physics

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