A particle has displacement of 12 ,m towards east and 5 ,m towards north then 6 ,m vertically upward

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3-2.Motion in Plane

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A particle has displacement of $12 \,m$ towards east and $5 \,m$ towards north then $6 \,m $ vertically upward. The sum of these displacements is........$m$

A$12$

B$10.04$

C$14.31$

DNone of these

(AIIMS-1998)

Solution

(c)$R = \sqrt {{{12}^2} + {5^2} + {6^2}} = \sqrt {144 + 25 + 36} = \sqrt {205} = 14.31\;m$

Standard 11

Physics

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