A person moves 30, m north and then 20, m tow | vedclass

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Question

(c) From figure, $\overrightarrow {OA} = 0\;\overrightarrow i + 30\;\overrightarrow j $, $\overrightarrow {AB} = 20\;\overrightarrow i + 0\;\overright

Vedclass · Accepted Answer

$10\, m$ along west

Vedclass · Answer

(c) From figure, $\overrightarrow {OA} = 0\;\overrightarrow i + 30\;\overrightarrow j $, $\overrightarrow {AB} = 20\;\overrightarrow i + 0\;\overrightarrow j $

$\overrightarrow {BC} = - 30\sqrt 2 \;cos{45^o}\overrightarrow i $$ - 30\sqrt 2 \;\sin {\rm{4}}{{\rm{5}}^{\rm{o}}}\overrightarrow j $ $ = - 30\;\overrightarrow i - 30\;\overrightarrow j $

Net displacement, $\overrightarrow {OC} = \overrightarrow {OA} + \overrightarrow {AB} + \overrightarrow {BC} $$ = - 10\;\overrightarrow i + 0\;\overrightarrow j $
$|\overrightarrow {OC} |\; = 10\;m.$

A person moves $30\, m$ north and then $20\, m$ towards east and finally $30\sqrt 2 \,m$ in south-west direction. The displacement of the person from the origin will be

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