A particle is moving in a circular path. acceleration and momentum of particle at a certain moment a

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3-2.Motion in Plane

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A particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are $\vec a = (4\hat i + 3\hat j)\ m/s^2$ and $\vec p = (8\hat i - 6\hat j)\ kg-m/s$ . The motion of the particle is

Auniform circular motion

Baccelerated circular motion

Cde-accelerated circular motion

Dwe can not say anything with $\vec a$ and $\vec p$ only

Solution

$\vec{a}=4 \hat{i}+3 \hat{j}$
$\vec{P}=8 \hat{i}-6 \hat{j}$
$a_{c}=\frac{V^{2}}{R}=4$
$a_{t}=\left(\frac{d V}{d t}\right)=3$

Standard 11

Physics

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