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5.Work, Energy, Power and Collision
normal
A particle of mass $7\, kg$ moving at $5\, m/s$ is acted upon by a variable force opposite to its initial direction of motion. The variation of force $F$ is shown as a function of time $t$.

A
at $t = 10\, s$ speed of particle is $5\, m/s$
B
at $t = 10\, s$ direction of motion of particle is reversed
C
at $t = 5\, s$ the particle will momentarily at rest
D
all the above options are correct.
Solution
Initial momentum $=35 \mathrm{\,Ns}$
Change in momentum $=$ area of graph
$=\frac{14 \times 10}{2}=70 \mathrm{\,Ns}$
Final momentum $=-35 \mathrm{\,Ns}$
Standard 11
Physics