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5.Work, Energy, Power and Collision
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A spring of force constant $K$ is first stretched by distance a from its natural length and then further by distance $b$. The work done in stretching the part $b$ is .............
A
$\frac{1}{2} K a(a-b)$
B
$\frac{1}{2} K a(a+b)$
C
$\frac{1}{2} K b(2 a+b)$
D
$\frac{1}{2} K b(a-b)$
Solution
(c)
$W_1=\frac{1}{2} k x^2=\frac{1}{2} k a^2$
$W_2=\frac{1}{2} k(a+b)^2$
$\Delta W=W_2-W_1=\frac{1}{2} k b(2 a+b)$
Standard 11
Physics
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