5.Work, Energy, Power and Collision
normal

A spring of force constant $K$ is first stretched by distance a from its natural length and then further by distance $b$. The work done in stretching the part $b$ is .............

A

$\frac{1}{2} K a(a-b)$

B

$\frac{1}{2} K a(a+b)$

C

$\frac{1}{2} K b(2 a+b)$

D

$\frac{1}{2} K b(a-b)$

Solution

(c)

$W_1=\frac{1}{2} k x^2=\frac{1}{2} k a^2$

$W_2=\frac{1}{2} k(a+b)^2$

$\Delta W=W_2-W_1=\frac{1}{2} k b(2 a+b)$

Standard 11
Physics

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