A particle of mass $m$ travelling along $x-$ axis with speed $v_0$ shoots out $1/3^{rd}$ of its mass with a speed $2v_0$ along $y-$ axis. The velocity of remaining piece is
${v_0}\left( {\frac{3}{2}\hat i - \hat j} \right)$
$\frac{{{v_0}}}{2}\left( {3\hat i - \hat j} \right)$
${v_0}\left( {\frac{1}{2}\hat i - 3\hat j} \right)$
$\frac{{{v_0}}}{2}\left( {\hat i + 3\hat j} \right)$
A space craft of mass $'M' $ and moving with velocity $ 'v' $ suddenly breaks in two pieces of same mass $m$. After the explosion one of the mass $ 'm'$ becomes stationary. What is the velocity of the other part of craft
A ball is projected from top of a tower with a velocity of $5\,\, m/s$ at an angle of $53^o$ to horizontal. Its speed when it is at a height of $0.45 \,\,m$ from the point of projection is ........ $m/s$
The potential energy function for a particle executing linear simple harmonic motion is given by $V(x)=$ $k x^{2} / 2,$ where $k$ is the force constant of the oscillator. For $k=0.5\; N m ^{-1}$ the graph of $V(x)$ versus $x$ is shown in Figure. Show that a particle of total energy $1 \;J$ moving under this potential must 'turn back" when it reaches $x=\pm 2 m$
The inclined surfaces of two movable wedges of same mass $M$ are smoothly conjugated with the horizontal plane as shown in figure. $A$ washer of mass $m$ slides down the left wedge from a height $h$. To what maximum height will the washer rise along the right wedge? Neglect friction.
Write the principle of conservation of mechanical energy for non-conservative force.