A particle starts from rest, accelerates at 2 | vedclass

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Question

(a) Velocity acquired by body in $10\,sec$
$v = 0 + 2 	imes 10 = 20\,m/s$
and distance travelled by it in $10 \,sec$
${S_1} = \frac{1}{2} 	imes 2

Vedclass · Accepted Answer

$750$

Vedclass · Answer

(a) Velocity acquired by body in $10\,sec$
$v = 0 + 2 	imes 10 = 20\,m/s$
and distance travelled by it in $10 \,sec$
${S_1} = \frac{1}{2} 	imes 2 	imes {(10)^2} = 100\;m$
then it moves with constant velocity (20 \,m/s)for $30\;\sec $
$\;{S_2} = 20 	imes 30 = 600\;m$
After that due to retardation $(4\,m/{s^2})$ it stops
${S_3} = \frac{{{v^2}}}{{2a}} = \frac{{{{(20)}^2}}}{{2 	imes 4}} = 50\,m$
Total distance travelled ${S_1} + {S_2} + {S_3} = 750\,m$

A particle starts from rest, accelerates at $2 \,ms^{-2}$ for $10\,s$ and then goes for constant speed for $30\,s$ and then decelerates at $ 4\, ms^{-2}$ till it stops. What is the distance travelled by it.........$m$

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