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2.Motion in Straight Line
medium
A particle starts its motion from rest under the action of a constant force. If the distance covered in first $10$ seconds is $S_1$ and that covered in the first $20$ seconds is $S_2$ , then
A$S_2=2S_1$
B$S_2=3S_1$
C$S_2=4S_1$
D$S_2=S_1$
(AIPMT-2009)
Solution
$\begin{array}{l}
Give\,\,u = 0.\\
{\rm{Distance}}\,{\rm{travelled}}\,{\rm{in}}\,10\,s,\,{S_1} = \frac{1}{2}a{.10^2} = 50a\\
{\rm{Distance}}\,{\rm{travelled}}\,{\rm{in}}\,20\,s,\,{S_2} = \frac{1}{2}a{.20^2} = 200a\\
\therefore \,{S_2} = 4{S_1}.
\end{array}$
Give\,\,u = 0.\\
{\rm{Distance}}\,{\rm{travelled}}\,{\rm{in}}\,10\,s,\,{S_1} = \frac{1}{2}a{.10^2} = 50a\\
{\rm{Distance}}\,{\rm{travelled}}\,{\rm{in}}\,20\,s,\,{S_2} = \frac{1}{2}a{.20^2} = 200a\\
\therefore \,{S_2} = 4{S_1}.
\end{array}$
Standard 11
Physics
