A pendulum clock keeps correct time at $0°C$. Its mean coefficient of linear expansions is $\alpha /^\circ C$, then the loss in seconds per day by the clock if the temperature rises by $t°C$ is
$\frac{{\frac{1}{2}\alpha \,t \times 864000}}{{1 - \frac{{\alpha \,t}}{2}}}$
$\frac{1}{2}\alpha \,t \times \,86400$
$\frac{{\frac{1}{2}\alpha \,t \times 86400}}{{{{\left( {1 - \,\frac{{\alpha \,t}}{2}} \right)}^2}}}$
$\frac{{\frac{1}{2}\alpha \,t \times 86400}}{{1 + \frac{{\alpha \,t}}{2}}}$
A metallic bar of Young's modulus, $0.5 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$ and coefficient of linear thermal expansion $10^{-5}{ }^{\circ} \mathrm{C}^{-1}$, length $1 \mathrm{~m}$ and area of cross-section $10^{-3} \mathrm{~m}^2$ is heated from $0^{\circ} \mathrm{C}$ to $100^{\circ} \mathrm{C}$ without expansion or bending. The compressive force developed in it is :
The weight of sphere in air is $50\ g$. Its weight $40\ g$ in a liquid, at temperature $20\,^o C$. When temperature increases to $70\,^o C$ , it weight becomes $45\ g$, then the ratio of densities of liquid at given two temperature is
In cold countries, water pipes sometimes burst, because
A blacksmith fixes iron ring on the rim of the wooden wheel of a horse cart. The diameter of the rim and the iron ring are $5.243\; m$ and $5.231\; m$, respectively at $27^oC$. To what temperature (in $^oC$) should the ring be heated so as to fit the rim of the wheel?
A steel rail of length $5\,m$ and area of cross-section $40\,cm^2$ is prevented from expanding along its length while the temperature rises by $10\,^oC$. If coefficient of linear expansion and Young's modulus of steel are $1.2\times10^{-5}\, K^{-1}$ and $2\times10^{11}\, Nm^{-2}$ respectively, the force developed in the rail is approximately