A person moved from A to B on a circular path | vedclass

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Question

$d = R 	heta$

$60= R \left(\frac{3 \pi}{4}ight)$

$R =\frac{60 	imes 4}{3 \pi}=\frac{80}{\pi} m$

Displacement $=\sqrt{ R ^{2}+ R ^{2}-2 R

Vedclass · Accepted Answer

$47$

Vedclass · Answer

$d = R 	heta$

$60= R \left(\frac{3 \pi}{4}ight)$

$R =\frac{60 	imes 4}{3 \pi}=\frac{80}{\pi} m$

Displacement $=\sqrt{ R ^{2}+ R ^{2}-2 R ^{2} \cos 135}$

$\Rightarrow \sqrt{2 R ^{2}-2 R ^{2}(-0.7)}$

$\Rightarrow \sqrt{3.4 R ^{2}}=\sqrt{3.4\left(\frac{80}{\pi}ight)^{2}}$

$\approx 47\,m$

A person moved from $A$ to $B$ on a circular path as shown in figure. If the distance travelled by him is $60 \,m$, then the magnitude of displacement would be$.....\,m$ (Given $\left.\cos 135^{\circ}=-0.7\right)$

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