A physical quantity is given by $X = {M^a}{L^b}{T^c}$. The percentage error in measurement of $M,L$ and $T$ are $\alpha ,\beta $ and $\gamma $ respectively. Then maximum percentage error in the quantity X is
$a\alpha + b\beta + c\gamma $
$a\alpha + b\beta - c\gamma $
$\frac{a}{\alpha } + \frac{b}{\beta } + \frac{c}{\gamma }$
None of these
The least count of stop watch is $\frac{1}{5}\,second$. The time of $20$ oscillations of pendulum is measured to be $25\,seconds$. Then percentage error in the measurement of time will be.......... $\%$
If $Z=\frac{A^{2} B^{3}}{C^{4}}$, then the relative error in $Z$ will be
The temperatures of two bodies measured by a thermometer are $t_{1}=20^{\circ} C \pm 0.5^{\circ} C$ and $t_{2}=50^{\circ} C \pm 0.5^{\circ} C$ Calculate the temperature difference and the error theirin.
Two resistors of resistances $R_{1}=100 \pm 3$ $ohm$ and $R_{2}=200 \pm 4$ $ohm$ are connected $(a)$ in series, $(b)$ in parallel. Find the equivalent resistance of the $(a)$ series combination, $(b)$ parallel combination. Use for $(a)$ the relation $R=R_{1}+R_{2}$ and for $(b)$ $\frac{1}{R^{\prime}}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$ and $\frac{\Delta R^{\prime}}{R^{\prime 2}}=\frac{\Delta R_{1}}{R_{1}^{2}}+\frac{\Delta R_{2}}{R_{2}^{2}}$
A student measures the time period of $100$ oscillations of a simple pendulum four times. The data set is $90\;s$ ,$91\;s $, $95\;s$ and $92\;s$. If the minimum division in the measuring clock is $1\;s$, then the reported mean time should be