1.Units, Dimensions and Measurement
medium

The maximum percentage errors in the measurement of mass (M), radius (R) and angular velocity $(\omega)$ of a ring are $2 \%, 1 \%$ and $1 \%$ respectively, then find the maximum percenta? error in the measurement of its rotational kinetic energy $\left(K=\frac{1}{2} I \omega^{2}\right)$

A

$3$

B

$6$

C

$4$

D

$1$

Solution

Rotational kinetic energy $(K)=\frac{1}{2} I \omega^{2}=\frac{1}{2} M R^{2} \omega^{2}$

$\therefore \frac{\Delta K}{K} \times 100=\frac{\Delta M}{M} \times 100+2 \frac{\Delta R}{R} \times 100+2 \frac{\Delta \omega}{\omega} \times 100$

$=2 \%+(2 \times 1 \%)=6 \%$

Standard 11
Physics

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