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10-1.Thermometry, Thermal Expansion and Calorimetry
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A piece of ice (heat capacity $=2100 \mathrm{~J} \mathrm{~kg}^{-1}{ }^{\circ} \mathrm{C}^{-1}$ and latent heat $=3.36 \times 10^5 \mathrm{~J} \mathrm{~kg}^{-1}$ ) of mass $\mathrm{m}$ grams is at $-5^{\circ} \mathrm{C}$ at atmospheric pressure. It is given $420 \mathrm{~J}$ of heat so that the ice starts melting. Finally when the ice-water mixture is in equilibrium, it is found that $1 \ \mathrm{gm}$ of ice has melted. Assuming there is no other heat exchange in the process, the value of $m$ is
A
$7$
B
$8$
C
$9$
D
$5$
(IIT-2010)
Solution
$420=\left(\mathrm{m} \times 2100 \times 5+1 \times 3.36 \times 10^5\right) \times 10^{-3}$
where $\mathrm{m}$ is in $\mathrm{gm}$.
Standard 11
Physics
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