A plane electromagnetic wave of wave intensity $6\, W/ m^2$ strikes a small mirror area $40 cm^2$, held perpendicular to the approaching wave. The momentum transferred by the wave to the mirror each second will be
$6.4 \times {10^{ - 7}}kg - m/{s^2}$
$4.8 \times {10^{ - 8}}kg - m/{s^2}$
$3.2 \times {10^{ - 9}}kg - m/{s^2}$
$1.6 \times {10^{ - 10}}kg - m/{s^2}$
The magnetic field in a plane electromagnetic wave is given by, $B=3.01 \times 10^{-7} \sin \left(6.28 \times 10^2 \times+2.2 \times 10^{10} t\right) \,T$. [where $x$ in $cm$ and $t$ in second]. The wavelength of the given wave is ....... $cm$
The electric field of an electromagnetic wave in free space is given by $\vec E$$=10 cos (10^7t+kx)$$\hat j$ $volt/m $ where $t$ and $x$ are in seconds and metres respectively. It can be inferred that
$(1)$ the wavelength $\lambda$ is $188.4\, m.$
$(2)$ the wave number $k$ is $0.33\,\, rad/m.$
$(4)$ the wave is propagating along $+x$ direction.
Which one of the following pairs of statements is correct ?
A charged particle oscillates about its mean equilibrium position with a frequency of $10^9 \;Hz$. What is the frequency of the electromagnetic waves produced by the oscillator?
A plane electromagnetic wave is propagating along the direction $\frac{\hat{i}+\hat{j}}{\sqrt{2}},$ with its polarization along the direction $\hat{\mathrm{k}}$. The correct form of the magnetic field of the wave would be (here $\mathrm{B}_{0}$ is an appropriate constant)
A plane electromagnetic wave with frequency of $30 {MHz}$ travels in free space. At particular point in space and time, electric field is $6 {V} / {m}$. The magnetic field at this point will be ${x} \times 10^{-8} {T}$. The value of ${x}$ is ..... .