A point source of $e. m.$ radiation has an average power output of $800\,W$ . The maximum value of electric field at a distance $4.0\,m$ from the source is...$V/m$
$68.20$
$54.77$
$50.32$
$48.10$
In a plane electromagnetic wave, the directions of electric field and magnetic field are represented by $\hat{ k }$ and $2 \hat{ i }-2 \hat{ j },$ respectively What is the unit vector along direction of propagation of the wave.
A plane electromagnetic wave is propagating along the direction $\frac{\hat{i}+\hat{j}}{\sqrt{2}},$ with its polarization along the direction $\hat{\mathrm{k}}$. The correct form of the magnetic field of the wave would be (here $\mathrm{B}_{0}$ is an appropriate constant)
An electromagnetic wave of frequency $\nu = 3.0\,MHz$ passes from vacuum into a dielectric medium with permitivity $\varepsilon = 4.0$. Then
The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by
$E _{ x }= E _0 \sin ( kz -\omega t )$
$B _{ y }= B _0 \sin ( kz -\omega t )$
Then the correct relation between $E_0$ and $B_0$ is given by
The nature of electromagnetic wave is :-