A positively charged ball hangs from a silk thread. We put a positive test charge {q

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1. Electric Charges and Fields

easy

A positively charged ball hangs from a silk thread. We put a positive test charge ${q_0}$ at a point and measure $F/{q_0}$, then it can be predicted that the electric field strength $E$

$ > F/{q_0}$

$ = F/{q_0}$

$ < F/{q_0}$

Cannot be estimated

Solution

(a) Because of the presence of positive test charge $q_0$ in front of positively charged ball, charge on the ball will be redistributed, less charge on the front half surface and more charge on the back half surface. As a result of this net force $F$ between ball and point charge will decrease i.e. actual electric field will be greater than $F/{q_0}.$

Standard 12

Physics

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medium

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medium

A positively charged ball hangs from a silk thread. We put a positive test charge ${q_0}$ at a point and measure $F/{q_0}$, then it can be predicted that the electric field strength $E$

Solution

Similar Questions

Select the correct statement : (Only force on a particle is due to electric field)

An oil drop carries six electronic charges, has a mass of $1.6 \times 10^{-12} g$ and falls with a terminal velocity in air. The magnitude of vertical electrical electric field required to make the drop move upward with the same speed as was formely moving is ……..$kN/C$

The electric field in a region is radially outward and at a point is given by $E=250 \,r V / m$ (where $r$ is the distance of the point from origin). Calculate the charge contained in a sphere of radius $20 \,cm$ centred at the origin ……… $C$

A charged particle of mass $5 \times {10^{ – 5}}\,kg$ is held stationary in space by placing it in an electric field of strength ${10^7}\,N{C^{ – 1}}$ directed vertically downwards. The charge on the particle is

Find ratio of electric field at point $A$ and $B.$ Infinitely long uniformly charged wire with linear charge density $\lambda$ is kept along $z-$ axis

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