A projectile is fired with a velocity at righ | vedclass

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Question

If $\mathfrak{t}$ is the line of flight, then

$o=v t-\frac{1}{2} g \cos 	heta t^{2}$

$t=\frac{2 v}{g \cos 	heta}$

$\Rightarrow R=\frac{1}{2

Vedclass · Accepted Answer

$\frac{{2{v^2}}}{g}	an \,	heta \,\,\sec \,	heta$

Vedclass · Answer

If $\mathfrak{t}$ is the line of flight, then

$o=v t-\frac{1}{2} g \cos 	heta t^{2}$

$t=\frac{2 v}{g \cos 	heta}$

$\Rightarrow R=\frac{1}{2} g \sin 	heta 	imes\left(\frac{2 v}{g \cos 	heta}ight)^{2}$

$R=\frac{2 v^{2}}{g} 	an 	heta \sec 	heta$

A projectile is fired with a velocity at right angle to the slope which is inclined at an angle $\theta$ with the horizontal. The expression for the range $R$ along the incline is

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