13.Nuclei
medium

A radioactive material has a half life of $10$ days. What fraction of the material would remain after $30$ days

A

$0.5$

B

$0.25$

C

$0.125$

D

$0.33$

(AIIMS-2005)

Solution

(c) $N = {N_0}{\left( {\frac{1}{2}} \right)^{\frac{t}{{{T_{1/2}}}}}}$

$ \Rightarrow \frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^{\frac{{30}}{{10}}}} = \frac{1}{8} = 0.125$.

Standard 12
Physics

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