A radioactive material of half-life $T$ was produced in a nuclear reactor at different instants, the quantity produced second time was twice of that produced first time. If now their present activities are $A_1$ and $A_2$ respectively then their age difference equals :
$\frac{T}{{\ln \,2}}\,\left| {\ln \,\frac{{{A_1}}}{{{A_2}}}} \right|$
$T\,\left| {\ln \,\frac{{{A_1}}}{{{A_2}}}} \right|$
$\frac{T}{{\ln \,2}}\,\,\left| {\ln \,\frac{{{A_2}}}{{2{A_1}}}} \right|$
$T\,\left| {\ln \,\frac{{{A_2}}}{{2{A_1}}}} \right|$
The nucleus $_{10}^{23} Ne$ decays by $\beta^{-}$ emission. Write down the $\beta$ -decay equation and determine the maximum kinetic energy of the electrons emitted. Given that
$m\left(_{10}^{23} Ne \right)=22.994466 \;u$
$m\left(_{11}^{23} Na\right) =22.089770\; u$
Write the law of radioactive decay.
The activity $R$ of an unknown radioactive nuclide is measured at hourly intervals. The results found are tabulated as follows:
$t(h)$ | $0$ | $1$ | $2$ | $3$ | $4$ |
$R(MBq)$ | $100$ | $35.36$ | $12.51$ | $4.42$ | $1.56$ |
$(i)$ Plot the graph of $R$ versus $t$ and calculate half-life from the graph.
$(ii)$ Plot the graph of $\ln \left( {\frac{R}{{{R_0}}}} \right) \to t$ versus $t$ and obtain the value of half-life from the graph.
Assertion : ${}^{90}Sr$ from the radioactive fall out from a nuclear bomb ends up in the bones of human beings through the milk consumed by them. It causes impairment of the production of red blood cells.
Reason : The energetic $\beta - $ particles emitted in the decay of ${}^{90}Sr$ damage the bone marrow
Give the different units of radioactivity and define them.