A scientist claims to have a perfect technique in which he can spontaneously convert an electron completely into energy in the laboratory without any other material required. What is the conclusion about this claim from our current understanding of physics?
This is possible because Einstein's equation says that mass and energy are equivalent... it is just very difficult to achieve with electrons
This is possible and it is done all the time in the high-energy physics labs.
The scientist is almost correct... except that in converting the electron to energy, an electron's anti-particle is produced in the process as well
This is not possible because charge conservation would be violated.
A nucleus at rest splits into two nuclear parts having same density and the radii in the ratio $1 : 2$ . Their velocities are in ratio ———
If the nucleus ${}_{13}^{27}Al$ has a nuclear radius of about $3.6\,\, fm,$ then ${ }_{32}^{125} Te$ would have its radius approximately as .......$fm$
Assume that the nuclear binding energy per nucleon $(B/A)$ versus mass number $(A)$ is as shown in the figure. Use this plot to choose the correct choice $(s)$ given below
$(A)$ Fusion of two nuclei with mass numbers lying in the range of $1 < A < 50$ will release energy
$(B)$ Fusion of two nuclei with mass numbers lying in the range of $51 < A < 100$ will release energy
$(C)$ Fission of a nucleus lying in the mass range of $100 < A < 200$ will release energy when broken into two equal fragments
$(D)$ Fission of a nucleus lying in the mass range of $200 < A < 260$ will release energy when broken into two equal fragments
A nucleus represented by the symbol ${ }_{Z}^{ A } X$ has
Define the different terms used for the composition of a nucleus.