Size of nucleus is of the order of

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(b) Size of nucleus, $R=R_{o} A^{1 / 3}$

where $R_{o}=1.5 \mathrm{fm}=1.5 	imes 10^{-15} \mathrm{m}$

and $A$ is the mass no.

$A^{1 / 3}$ is

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${10^{ - 15}}m$

Vedclass · Answer

(b) Size of nucleus, $R=R_{o} A^{1 / 3}$

where $R_{o}=1.5 \mathrm{fm}=1.5 	imes 10^{-15} \mathrm{m}$

and $A$ is the mass no.

$A^{1 / 3}$ is of order $1$

hence $R$ is of order $10^{-15} \mathrm{m}$

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