A simple pendulum has time period 't'. Its time period in a lift which is moving upwards with acceleration $3 ms ^{-2}$ is

  • A

    $t \sqrt{\frac{9.8}{12.8}}$

  • B

    $t \sqrt{\frac{12.8}{9.8}}$

  • C

    $t \sqrt{\frac{9.8}{6.8}}$

  • D

    $t \sqrt{\frac{6.8}{9.8}}$

Similar Questions

Two simple pendulums of length $0.5\, m$ and $2.0\, m$ respectively are given small linear displacement in one direction at the same time. They will again be in the phase when the pendulum of shorter length has completed .... oscillations.

  • [AIPMT 1998]

A pendulume clock loses $12\;s$ a day if the temperature is $40^oC$ and gains $4\;s$ a day if the temperature is $20^oC$. The temperature at which the clock will show correct time, and the coeffecient of linear expansion $(\alpha)$ of the metal of the pendulum shaft are respectively

  • [JEE MAIN 2016]

If two persons sitting on a swing instead of one, why the periodic time does not changed ?

There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is $T$. If the resultant acceleration becomes $g/4,$ then the new time period of the pendulum is

To show that a simple pendulum executes simple harmonic motion, it is necessary to assume that