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A hollow sphere is filled with water through a small hole in it. It is then hung by a long thread and made to oscillate. As the water slowly flows out of the hole at the bottom, the period of oscillation will
Continuously decrease
Continuously increase
First decrease and then increase to original value
First increase and then decrease to original value
Solution
(d) The given system is like a simple pendulum, whose effective length $(l)$ is equal to the distance between point of suspension and $C.G.$ (Centre of Gravity) of the hanging body.
When water slowly flows out the sphere, the $C.G.$ of the system is lowered, and hence $l$ increases, which in turn increases time period (as $T \propto \sqrt l $).
After some time weight of water left in sphere become less than the weight of sphere itself, so the resultant $C.G.$ gets clear the $C.G.$ of sphere itself i.e. $l$ decreases and hence $T$ increases.
Finally when the sphere becomes empty, the resulting $C.G.$ is the $C.G.$ of sphere
i.e. length becomes equal to the original length and hence the time period becomes equal to the same value as when it was full of water.
