The bob of simple pendulum having length l, i | vedclass

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Question

(c)If suppose bob rises up to a height h as shown then after releasing potential energy at extreme position becomes kinetic energy of mean position
$

Vedclass · Accepted Answer

$\sqrt {2gl(1 - \cos 	heta )} $

Vedclass · Answer

(c)If suppose bob rises up to a height h as shown then after releasing potential energy at extreme position becomes kinetic energy of mean position
$ \Rightarrow mgh = \frac{1}{2}mv_{\max }^2$

$ \Rightarrow {v_{\max }} = \sqrt {2gh} $
Also, from figure $\cos 	heta = \frac{{l - h}}{l}$
$ \Rightarrow h = l(1 - \cos 	heta )$
So, ${v_{\max }} = \sqrt {2gl(1 - \cos 	heta )} $

The bob of simple pendulum having length $l$, is displaced from mean position to an angular position $\theta$ with respect to vertical. If it is released, then velocity of bob at lowest position

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