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10-2.Transmission of Heat
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A slab consists of two parallel layers of two different materials of same thickness having thermal conductivities $K_1$ and $K_2$ . The equivalent conductivity of the combination is
A
${K_1} + {K_2}$
B
$\frac{{{K_1} + {K_2}}}{2}$
C
$\frac{{2{K_1}{K_2}}}{{{K_1} + {K_2}}}$
D
$\frac{{{K_1} + {K_2}}}{{2{K_1}{K_2}}}$
Solution
(b) In parallel combination equivalent conductivity
$K = \frac{{{K_1}{A_1} + {K_2}{A_2}}}{{{A_1} + {A_2}}} = \frac{{{K_1} + {K_2}}}{2}$ (As ${A_1} = {A_2}$)
Standard 11
Physics
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