A small sphere carrying a charge ‘$q$’ is hanging in between two parallel plates by a string of length $L$. Time period of pendulum is ${T_0}$. When parallel plates are charged, the time period changes to $T$. The ratio $T/{T_0}$ is equal to
${\left( {\frac{{g + \frac{{qE}}{m}}}{g}} \right)^{1/2}}$
${\left( {\frac{g}{{g + \frac{{qE}}{m}}}} \right)^{3/2}}$
${\left( {\frac{g}{{g + \frac{{qE}}{m}}}} \right)^{1/2}}$
None of these
$0.2\, F$ capacitor is charged to $600\, V$ by a battery. On removing the battery. It is connected with another parallel plate condenser of $1\, F$. The potential decreases to....$V$
The radius of a metallic sphere if its capacitance is $1/9\,F$, is
Two metal spheres of capacitance ${C_1}$ and ${C_2}$ carry some charges. They are put in contact and then separated. The final charges ${Q_1}$ and ${Q_2}$ on them will satisfy
Two spherical conductors $A$ and $B$ of radii $a$ and $b$ $(b > a)$ are placed concentrically in air. The two are connected by a copper wire as shown in figure. Then the equivalent capacitance of the system is
What is capacitor ? And explain capacitance. Give its $\mathrm{SI}$ unit.